log[2](3x+1)=6

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Solution for log[2](3x+1)=6 equation:


Simplifying
log[2](3x + 1) = 6

Reorder the terms:
glo * 2(1 + 3x) = 6

Reorder the terms for easier multiplication:
2glo(1 + 3x) = 6
(1 * 2glo + 3x * 2glo) = 6
(2glo + 6glox) = 6

Solving
2glo + 6glox = 6

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-6 + 2glo + 6glox = 6 + -6

Combine like terms: 6 + -6 = 0
-6 + 2glo + 6glox = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-3 + glo + 3glox) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-3 + glo + 3glox)' equal to zero and attempt to solve: Simplifying -3 + glo + 3glox = 0 Solving -3 + glo + 3glox = 0 Move all terms containing g to the left, all other terms to the right. Add '3' to each side of the equation. -3 + glo + 3 + 3glox = 0 + 3 Reorder the terms: -3 + 3 + glo + 3glox = 0 + 3 Combine like terms: -3 + 3 = 0 0 + glo + 3glox = 0 + 3 glo + 3glox = 0 + 3 Combine like terms: 0 + 3 = 3 glo + 3glox = 3 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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